Heat and temperature

mass of aluminum = m1= 8 g
mass of copper = m2= 18 g

volume of ethyl alcohol= 55 cc
density of ethyl alcohol= 0.789 g/cc
therefore mass of ethyl alcohol is= m3= 43.395 g =55*0.789

specific heat capacity of
Aluminum= 900 J/Kg/K or 0.9 J/g/K
Copper= 386 J/Kg/K or 0.386 J/g/K
Ethyl alcohol= 2430 J/Kg/K or 2.43 J/g/K

initial temperature
Aluminum= 200 degree C
Copper= ? T degree C
Ethyl alcohol= 15 degree C

final temperature= 24 degree C

Heat loss from Aluminum and Copper = Heat gain by Ethyl alcohol

or 8 x 0.9 x (200-24) + 18 x 0.386 x (T-24) = 43.395 x 2.43 x (24-15)

or Solving for T
T= -21.8 degree C

Answer: Temperature of Copper= -21.8 degree C

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