Explore BrainMass

Explore BrainMass

    Chemistry Problem Set: Heat Energy and Temperature

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    The specific heat capacity of benzene is 1.74J/g*K. What is its molar heat capacity (Jmol*K)?

    What quanity of heat is required to raise the temperature of 50.00mL of water from 25.52 to 28.75C? The density of water at this temperature is 0.997 g/mL.

    When 108g of water at a temperature of 22.5C is mixed with 65.1g of water at an unknown twmperature, the final temperature of the resulting mixture is 47.9C. What was the initial temperature of the sample of water?

    What quanity of heat energy (in joules) is required to raise the temperature of 454g of tin from room temperature (25.0C) to its melting point, 231.9C and then melt the tin at that temperature? The specific heat capacity of tin is 0.227 J/g*K, and the heat fusion of this metal is 59.2J/g.

    © BrainMass Inc. brainmass.com March 4, 2021, 5:53 pm ad1c9bdddf
    https://brainmass.com/chemistry/energetics-and-thermodynamics/chemistry-problem-set-heat-energy-temperature-16040

    Solution Preview

    The specific heat capacity of benzene is 1.74J/g*K. What is its molar heat capacity (Jmol*K)?

    Molar heat capacityBenzene = specific heat capacityBenzene * MolarMassBenzene
    = (1.74 J/g*K ) * ( 78 g/mol )
    = 135.72 J/mol*K

    What quanity of heat is required to raise the temperature of 50.00mL of water from 25.52 to ...

    Solution Summary

    Molar heat capacityBenzene = specific heat capacityBenzene * MolarMassBenzene
    Heat = mass of water * specific heat of water * temperature difference
    Heat of Sample1 = (-)Heat of Sample2
    Total Heat = massTin * specific heat capacityTin* Temperature difference + Heat fusionTin* massTin

    $2.49

    ADVERTISEMENT