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Molarity and equilibrium

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A sodium hydroxide solution was standardized by weighing 2.425 g of oxalic acid, H2C2O4*2H2o and diluting it to 250 mL in a volumetric flask. Then 25.0 mL of this acid solution was titrated with 30.20 mL of base.

Based on this information, how do I calculate the molarity of the sodium hydroxide solution?

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Solution Summary

This solution is provided in 451 words and uses a balanced chemical equation to calculate number of moles.

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In order to answer this question, we must first ask what sodium hydroxide and oxalic acid do when they react. Oxalic acid is a diprotic acid, and it will donate two protons to the hydroxide to neutralize it. Hence the balanced chemical equation for your reaction will be:

H2C2O4 + 2NaOH ----> Na2C2O4 + 2H20

What this equation is telling you is that for every mole of oxalic acid you have, two moles of NaOH will be needed to completely react with it. Equilibrium will not be an issue here; the reaction will, for all intents and purposes, go to completion (you can ...

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