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# Working with the decomposition of sucrose in acidic medium

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Sucrose decomposes in acid solution, according to the first order rate law, to give Glucose and fructose. If the half life for the reaction is 3.33 hours at 25 degree celcius, what fraction of a sample of sucrose would remain after 9 hours ?

https://brainmass.com/chemistry/acids-and-bases/working-decomposition-sucrose-acidic-medium-8751

## SOLUTION This solution is FREE courtesy of BrainMass!

Half life t_Â½ = 0.693/k

and k = 0.693/3.33 = 0.208 /hr

let the initial concentration be 1 mol/liter

now we can write,

0.208 = (2.303/9) * log(1/x)

where x is the concentration left behind after 9 hours

log (1/x) = 0.8129

or, x = 0.1538

The fraction of sucrose remaining after 9 hours = 0.154 mole/liter

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!