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    Working with the decomposition of sucrose in acidic medium

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    Sucrose decomposes in acid solution, according to the first order rate law, to give Glucose and fructose. If the half life for the reaction is 3.33 hours at 25 degree celcius, what fraction of a sample of sucrose would remain after 9 hours ?

    © BrainMass Inc. brainmass.com December 24, 2021, 4:48 pm ad1c9bdddf
    https://brainmass.com/chemistry/acids-and-bases/working-decomposition-sucrose-acidic-medium-8751

    SOLUTION This solution is FREE courtesy of BrainMass!

    Half life t_½ = 0.693/k

    and k = 0.693/3.33 = 0.208 /hr

    let the initial concentration be 1 mol/liter

    now we can write,

    0.208 = (2.303/9) * log(1/x)

    where x is the concentration left behind after 9 hours

    log (1/x) = 0.8129

    or, x = 0.1538

    The fraction of sucrose remaining after 9 hours = 0.154 mole/liter

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 4:48 pm ad1c9bdddf>
    https://brainmass.com/chemistry/acids-and-bases/working-decomposition-sucrose-acidic-medium-8751

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