Many people think that a national lobby's successful fight against gun control legislation is reflecting the will of a minority of Americans. A previous random sample of 4000 citizens yielded 2250 who are in favor of gun control legislation. How many citizens would need to be sampled if a 90% confidence intervals was desired to estimate the true proportion to within 5%?
we can compute the sample mean of the proportion p^=2250/4000=0.5625. Given ...
This solution show step-by-step calculations to determine the true proportion of citizens that are in favor of gun control in a 90% confidence interval.