Probability
Not what you're looking for?
Please see attached files for question. I can't seem to get the answer for PART3.
(See attached file for full problem description with equations)
---
A bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up window occur at random, with a mean arrival rate of 24 customers per hour or 0.4 customers per minute.
1) What is the mean or expected number of customers that will arrive in a five minute period?
Denote by the number of customers in the i-th minute. So, . Hence,
2) Assume that the Poisson probability distribution can be used to describe the arrival process. Use the mean arrival rate in part 1 and compute the probabilities that exactly 0, 1, 2, and 3 customers will arrive during a five-minute period.
By part 1), we know that the mean or expected number of customers that will arrive in a five minute period is 2. So, . Denote by X the number of customers will arrive during a five-minute period.
3) Delays are expected if more than three customers arrive during any five-minute period. What is the probability thsat delays will occur?
P(X>3)=1-P(X=0)-P(X=1)-P(X=2)-P(X=3)
=1-
So, the probability thsat delays will occur is 0.145
---
Purchase this Solution
Solution Summary
The solution clearly explains the steps required to get to the answer. The steps are explained in a very easy to understand manner and can be easily followed along by anyone with a basic understanding of probability. Overall, an excellent response to the question being asked.
Solution Preview
For the part 3), since by part 2), we know ...
Education
- BSc , Wuhan Univ. China
- MA, Shandong Univ.
Recent Feedback
- "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
- "excellent work"
- "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
- "Thank you"
- "Thank you very much for your valuable time and assistance!"
Purchase this Solution
Free BrainMass Quizzes
Know Your Statistical Concepts
Each question is a choice-summary multiple choice question that presents you with a statistical concept and then 4 numbered statements. You must decide which (if any) of the numbered statements is/are true as they relate to the statistical concept.
Measures of Central Tendency
Tests knowledge of the three main measures of central tendency, including some simple calculation questions.
Measures of Central Tendency
This quiz evaluates the students understanding of the measures of central tendency seen in statistics. This quiz is specifically designed to incorporate the measures of central tendency as they relate to psychological research.
Terms and Definitions for Statistics
This quiz covers basic terms and definitions of statistics.