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Probability

How many ways can 6 distinguishable balls be placed in 5 boxes such that there are 2 balls in the first box, and one in all remaining boxes?

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Solution Preview

For the first box, it is a combination of choosing 2 out of 6.
Then there are
(6)C(2) = 6! / [2!*(6-2)!] = ...

Solution Summary

How many ways can 6 distinguishable balls be placed in 5 boxes such that there are 2 balls in the first box, and one in all remaining boxes?

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