Statistics: Conducting a One-Way ANOVA
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A psychologist believes that the kind of feedback a person receives about their work affects the quality of the work. You randomly assign 12 widget makers to one of three groups: positive feedback only, corrective feedback only, and no feedback. You track the number of widgets that each person makes correctly (out of 10) and obtain the following data:
Positive Feedback Only Corrective Feedback Only No Feedback
5 4 5
4 5 4
4 3 6
7 6 2
Use an analysis of variance (alpha = 0.05) to determine whether this data is sufficient to conclude that there are significant differences between the feedback conditions.
Make sure you include a complete ANOVA summary table. Also, report the appropriate null and research hypotheses and the critical value (alpha = 0.05). In addition, provide your statistical conclusion, including a calculation of the test statistic, in the APA format and a conceptual conclusion in one to two sentences.
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Solution Summary
This solution is comprised of a detailed explanation of the various aspects of Analysis of Variance as it pertains to the given problem and provides students with a clear perspective of the calculations and underlying concepts required. Two files are attached, an Excel spreadsheet and a Word document which contain material pertaining to this solution.
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Null Hypothesis: There is no difference between the mean numbers of widgets among the three groups based on feedback conditions.
Alternate Hypothesis: There is a significant difference between the mean numbers of widgets among the three groups based on feedback conditions.
Analysis Plan:
We shall use significance ...
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