Temperature related to resulting mixtures of steam and condensed water
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300 grams of water at 0 degrees are placed in a copper container weighing 120 grams in which 35 grams of ice (at 0 degrees also). 17 grams of steam at 100 degrees are fed in and completely condensed to water. What is the temperature of the resulting mixtures.
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Let us assume the final temperature of the mixture be T degree C.
Heat energy taken by 300 gm [email protected] degC + 35 gm ice @0 degC + 120 gm copper container @ 0 degC
= Heat energy given by steam of 17 gm @ 100 degC
sp. heat of water sw= 1 cal/gm/C = ...
Solution Summary
With good explanations and calculations, the problem is explained and solved. The temperature of resulting mixtures is determined.
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