Two reversible heat engines X and Y are arranged in series. The engine X rejected heat directly to Y. Engine X receives 400 KJ of heat at 427 degrees centigrade from a high temperature source. Engine Y rejects heat to a sink at 7 degree centigrade. If the output of X is twice that of Y, find the efficiency of each engine, the heat rejected by engine X (i.e. Heat received by engine Y), and the heat rejected to the sink.© BrainMass Inc. brainmass.com June 4, 2020, 5:05 am ad1c9bdddf
You can solve this problem by using second law of thermodynamics and Clausius inequality for reversible heat engines. Here heat rejected by engine X is the input of engine Y and heat rejected by engine Y goes to the sink.
As both the engines are reversible we can use Clausius inequality (Second law of thermodynamics), which is,
Q1/T1 = Q2/T2
where, Q1 is input heat to the engine X from source having ...
This solution looks at two reversible heat engines arranged in series and calculates the heat rejected by engine Y to the sink by using Clausius inequality and provides step by step calculations of other quantities.