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Carnot Cycle - Efficiency of heat engines

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A Carnot engine operating at 30% efficiency exhausts heat into a heat sink at 283 K. By how much would the temperature of the heat reservoir need to be raised to increase the efficiency of the engine to 45%

I believe the answer is 111 K. I need to see each step and formula to solve this question. Please assume I know nothing because this would be the correct assumption.

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Efficiency of a Carnot Engine is given by, E = [1 - (T2/T1)]*100

where T1 > T2, T1 is the temperature of the source and T2 is that of ...

Solution Summary

The solution analyzes the Carnot cycle and the efficiency of a heat engine.

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