Purchase Solution

Carnot Cycle - Efficiency of heat engines

Not what you're looking for?

Ask Custom Question

A Carnot engine operating at 30% efficiency exhausts heat into a heat sink at 283 K. By how much would the temperature of the heat reservoir need to be raised to increase the efficiency of the engine to 45%

I believe the answer is 111 K. I need to see each step and formula to solve this question. Please assume I know nothing because this would be the correct assumption.

Purchase this Solution
Solution Summary

The solution analyzes the Carnot cycle and the efficiency of a heat engine.

Solution Preview

Efficiency of a Carnot Engine is given by, E = [1 - (T2/T1)]*100

where T1 > T2, T1 is the temperature of the source and T2 is that of ...

Purchase this Solution
Free BrainMass Quizzes
Basic Physics

This quiz will test your knowledge about basic Physics.

Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

The Moon

Test your knowledge of moon phases and movement.

Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

View More Free Quizzes
Related BrainMass Solutions

  • The Carnot Cycle and the efficiency of engines

    85648 The Carnot Cycle and the efficiency of engines A Carnot heat engine takes in 100 J at a temperature of 100^oC. At the end of the cycle, 50 J are exhausted. What is the temperature of the exhaust?

  • Carnot Heat engines operating in series

    Efficiency of a Carnot Heat Engine = N = 1 - (Tr/Ta) where Tr = Rejection Temperature in deg. K and Ta = Heat Addition Temperature in deg.

  • Carnot Engine

    Find the Temperature of the steam serving as the hot reservoir. I know the efficiency of Carnot engine is 1- (T_c/T_h) and the thermal efficiency of a heat engine is 1- (Q_c/Q_h). I'm not sure how to set this up. Can you help?

  • Isothermal Carnot Cycle

    35320 Isothermal Carnot Cycle During the isothermal heat addition process of a Carnot cycle, 900 kJ of heat is added to the working fluid from a source at 400 degrees Celcius.

  • A heat engine is operating on a Carnot cycle

    96617 A heat engine is operating on a Carnot cycle A heat engine is operating on a Carnot cycle and has a thermal efficiency of 55 percent. The waste heat from this engine is rejected to a nearby lake at 60 °F at a rate of 800 Btu/min.

  • Carnot Cycle for an Ideal Gas

    97026 Carnot Cycle for an Ideal Gas In our work with the Carnot cycle for an ideal gas, an equation similar to (1) below was derived, where q2 is the heat taken in at T2 and q1 is the heat expelled at T1.

  • Ideal Gases & Constant Heat Capacity

    So in our case the efficiency of the engine is: This is consistent for the property of the Carnot cycle that 2. Two identical bodies of constant heat capacity are initially at temperatures T1 and T2.

  • Thermodynamics: Efficiency of a Carnot cycle

    211954 Thermodynamics: Efficiency of a Carnot cycle I need a calculation of the 'Carnot cycle' and a proof of the 'efficiency expression. Efficiency expression: e = benefit / cost = W / Q Q = heat absorbed Please see the attached file.

  • Heat Engine

    In case of a heat engine maximum efficiency is achieved when it operates in Carnot Cycle.

View More Related Solutions