Charge on the capacitors when reconnected oppositively.
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Two capacitors, with capacitance 4.20*10^-6 F and 5.90*10^-6 F, are connected in parallel across a 660-V supply line.
The charged capacitors are disconnected from the line and from each other, and then reconnected to each other with terminals of unlike sign together.
a) find the final charge on the 4.20*10^-6 F capacitor?
b) find the final charge on the 5.90*10^-6 F capacitor?
c) find the final voltage across the 4.20*10^-6 F capacitor?
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Solution Summary
Two capacitors are charged with a battery and then after disconnecting, reconnecting them in parallel with opposite terminal together. The final charges and voltage are calculated.
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capacitor disconnected then reconnected (not hard just confusing)
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question states:
Two capacitors, with capacitance 4.20*10^-6 F and 5.90*10^-6 F, are connected in parallel across a 660-V supply line.
The charged capacitors are disconnected from the line and from each other, and then reconnected to each other with ...
Purchase this Solution
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