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    Charge on the capacitors when reconnected oppositively.

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    Two capacitors, with capacitance 4.20*10^-6 F and 5.90*10^-6 F, are connected in parallel across a 660-V supply line.

    The charged capacitors are disconnected from the line and from each other, and then reconnected to each other with terminals of unlike sign together.

    a) find the final charge on the 4.20*10^-6 F capacitor?
    b) find the final charge on the 5.90*10^-6 F capacitor?
    c) find the final voltage across the 4.20*10^-6 F capacitor?

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    Solution Preview

    Please see the attached file.

    capacitor disconnected then reconnected (not hard just confusing)
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    question states:

    Two capacitors, with capacitance 4.20*10^-6 F and 5.90*10^-6 F, are connected in parallel across a 660-V supply line.

    The charged capacitors are disconnected from the line and from each other, and then reconnected to each other with ...

    Solution Summary

    Two capacitors are charged with a battery and then after disconnecting, reconnecting them in parallel with opposite terminal together. The final charges and voltage are calculated.

    $2.49

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