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Physics: Potential Difference of a Capacitor

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Please solve and explain problem.

Part 1:

A 0.410 mF (C1) and a 0.630 mF (C2) capacitor are connected in series to a 12.00 V battery. Calculate the potential difference across C1.

Part 2:

Calculate the charge on C2.

Part 3:

Now assume that the two capacitors are connected in parallel. Calculate the voltage difference across C1.

Part 4:

Calculate the charge on C2.

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Solution Summary

This posting contains the solution to the given problems.

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1. The total capacitance in series is:
C = (0.41mF)(0.63mF)/(0.41mF+0.63mF)
C = 0.248mF
The total stored charge is:
q = CVbatt
q = ...

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