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    Capacitance

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    1. When a charge of 180 microC is applied to the plates of a capacitor, the potential difference between the plates is 15 V. What is the capacitance?

    2. How much charge is stored on each plate of a 5000 MicroF capacitor whose plates are held at a potential difference of 350 V?

    3.Calculate the capacitance of two flat metal pie pans 23 cm in diameter separated by 2.0 mm.

    4.A parallel-plate capacitor has plates with an area of 250 cm^ separated by 1.0 mm. What is the electric field between the plates when they are charged with 0.50 microC?

    5. What must be the minimium thicknes of a dielectric layer of pentoxide if the capacitor must withstand 50 V?

    6. How much energy is stored on a 1000-MicroF capacitor that is charged to potential difference of 500 V?

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    Solution Preview

    Note:We will use SI system of units in calculations
    ^ denotes power, * denotes multiplication

    1. When a charge of 180 microC is applied to the plates of a capacitor, the potential difference between the plates is 15 V. What is the capacitance?

    Charge=q= 180 Mu C = 0.00018 C
    Potential Difference=V= 15 V

    Capacitance=C= Charge/Potential difference=q/V= 0.000012 farad =0.00018/15

    One (1.0) microfarad is equal to 0.000001 farad or 1 X 10-6 farad
    Therefore 1 farad= 10^6 microfarad
    Therefore Capacitance C= 0.000012 farad = 12 Mu f

    Answer: Capacitance= 12 Mu F or microfarad

    2. How much charge is stored on each plate of a 5000 MicroF capacitor whose plates are held at a potential difference of 350 ...

    Solution Summary

    Answers 5 questions on Capacitance

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