Hi. Can someone please walk me through how to do the following problem?
Two capacitors, one 7.5 micro-F and the other 15 micro-F are connected in a series across a 12-V battery. (a) Find the equivalent capacitance of the two capacitors. (b) Which capacitor stores more charge. Explain. (c) Find the charge stored on each capacitor.
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When two capacitors are connected in series the equivalent capacitance is given by,
1/C_eq = 1/c1 + 1/c2
C_eq = c1*c2/[c1+c2]
Thus here, C_eq = 7.5*10^-6*15*10^-6/[7.5+15]*10^-6
= 5*10^-6 Farad = 5 microfarad ...
The capacitor stores with charges are examined. The answer is given step-by-step equationally.