Explore BrainMass

Explore BrainMass

    Capacitance and electric potential

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    A 2.61 micro F capacitor is charged to 1380 V and a 7.79 micro F is charged to 490 V. These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the negative plates are connected to each other.
    What will be the charge on the 2.61 micro F capacitor and what will be the charge on the 7.79 micro F capacitor?
    What will be the final potential difference across their assembly?

    © BrainMass Inc. brainmass.com March 6, 2023, 1:17 pm ad1c9bdddf

    Solution Preview

    When capacitors are connected in parallel, effective capacitance = C1+C2 = 2.61+7.79 = 10.4 micro ...

    Solution Summary

    Solution starts with computing the effective capacitance when capacitors are connected in parallel.