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Capacitors in series and parallel

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Two condensers are connectedin series across a 100V supply and is found that the potential difference across A is 60V. A condenser of 2mf capacitor is now connected in parallel with A and the potential difference across B rises to 90V. Then the capacitors of A and B are respectively (a) 0.24mf, 0.16mf (b)).16mf,0.24mf (c) 1.6mf 2.4mf (d)2.4mf. 1.6mf (c) 24mf 16mf

ANSWER IS C but how do you arrive at C? Thanks,

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Solution Summary

It explains how to calcualte the capacitance when capacitors are in series and parallel.

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first of all, capacitance C = Q/ V, where Q is the charge on the plates and V is the potential difference across.

when the two capacitors in series, the charges on them are equal.
for A: Q = C1 * V1
for B: Q = C2 * V2.
since we know ...

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