Solving trigonometric identities.
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Solve for x:
a) sin(^2)x=cosx-1
b) sin2x=cosx
c) sin2x=2sinx
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a) Note that sin(^2)x = 1-cos(^2)x
So the equation is
1-cos(^2)x=cosx-1
cos(^2)x+cosx-2=0
Let y=cosx
Then we need to solve y^2+y-2=0
y=(-1+sqrt(1-(-2*4)))/2 and
y=(-1-sqrt(1-(-2*4)))/2
So ...
Solution Summary
Trigonometric identities are solved.
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