a) Prove that tan 15degrees = 2 - sqrt(3).
b) Solve, for 0 </= theta < 360 degrees,
sin (theta + 60 degrees)sin (theta - 60 degrees) = (1 - sqrt(3)) cos^2(theta)
Solution of part(a)
tan(a - b) = [tan a - tan b]/[1 + (tan a)(tan ...
This solution looks at finding the solution in (a) by rationalizing the function as well as the solution to (b), with step by step calculations provided in an attached Word document.