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Proving Trigonometric Identities for sec, tan, cos and sin

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Prove
sec 2A + tan 2A = (cos A + sin A)/ (cos A - sin A)

Express this as a sum of 2 trigo functions
2(siny)(sin5y)

Prove
(sin2A)^2 - (sinA)^2 = (sinA)(sin3A)

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Trigonometric identities are proven. The solution is detailed and well presented.

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Prove
1) sec 2A + tan 2A = (cos A + sin A)/ (cos A - sin A)

2) Express this as a sum of 2 trigo functions= 2(siny)(sin5y)

3)Prove (sin2A)^2 - (sinA)^2 = (sinA)(sin3A)

Solution:

1) Taking the left hand side first we get,
LHS => sec2A + tan2A =
Taking LCD as 'cos2A', we get:

------- (1)

Taking right hand side

and ...

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