Explore BrainMass
Share

# Applications of the Pythagorean Theorem

This content was STOLEN from BrainMass.com - View the original, and get the already-completed solution here!

Measure the height of your computer monitor to the nearest tenth of a centimeter or sixteenth of an inch. Measure the width of your monitor as well. Use the Pythagorean theorem to find the length of the diagonal of your monitor.

In your post, include the height, the width, and the calculations needed to determine the length of the diagonal of your computer monitor. After you have calculated the approximate length using the Pythagorean theorem, use a measuring device to measure the length of the diagonal of your monitor. Was your measurement close? Why might the measurements not be exactly the same?

Typing hint: Type Pythagorean theorem as a^2 + b^2 = c^2. Do not use special graphs or symbols because they will not appear when pasted to the discussion board.

Part 2: Using the Library, web resources, and/or other materials, find a real-life application of a quadratic function. State the application, give the equation of the quadratic function, and state what the x and y in the application represent. Choose at least two values of x to input into your function and find the corresponding y for each. State, in words, what each x and y means in terms of your real-life application. Please see the following example. Do not use any version of this example in your own post. You may use other variables besides x and y, such as t and S depicted in the following example, but you may not use that example. Be sure to reference all sources using APA style.

Typing hint: To type x-squared, use x^2. Do not use special graphs or symbols because they will not appear when pasted to the Discussion Board.

When thrown into the air from the top of a 50 ft building, a ball's height, S, at time t can be found by S(t) = -16t^2 + 32t + 50. When t = 1, s = -16(1)^2 + 32(1) + 50 = 66. This implies that after 1 second, the height of the ball is 66 feet. When t = 2, s = -16(2)^2 + 32(2) + 50 = 50. This implies that after 2 seconds, the height of the ball is 50 feet.