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    Simple Geometry : Constructing a Golden Triangle

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    Given a line segment of length 1 inch, how do I construct a line segment of squareroot(6), squareroot(7), squareroot(8), etc.
    Also, given a wire of total length 4236 feet, how do I construct a golden triangle from the wire?

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    Solution Preview

    1. Draw a line segment AB of length 1 inch. Now, extend AB to C such that BC = X inches when squareroot(X) is desired. Now with line AC (of total length X+1 inches) as diameter, draw a semicircle. Draw a vertical line from B to intersect ...

    Solution Summary

    A "golden triangle" is constructed from a legth of wire. Line segments are investigated.