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    Prove this version of the Law of Cosines b^2 = a^2 + c^2 - 2ac cosA

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    Consider a triangle with sides a, b and c and angles A, B and C. Prove the following version of the Law of Cosines :

    b^2 = a^2 + c^2 - 2ac cosA

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    https://brainmass.com/math/geometry-and-topology/prove-version-law-cosines-5302

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    Solution Summary

    A version of the law of cosines is proven. A triangle with sides a, b, and c are found.

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