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Probability in a Grab Bag

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A grab bag contains 10 $1 prizes, 7 $5 prizes, and 5 $20 prizes. Three prizes are chosen at random. Find the following probabilities.

The probability that exactly two $20 prizes are chosen is
(Round to nearest thousandth as needed)

The probability that one of each prize is chosen is
(Round to nearest thousandth as needed)

The probability that at least on $20 prize is chosen is
(Round to nearest thousandth as needed)

The probability that no $1 prizes are chosen is
(Round to nearest thousandth as needed)

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Solution Summary

The expert examines the probability in a grab bag.

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The grab bag contains 10 $1 prizes, 7 $5 prizes, and 5 $20 prizes. Thus, in all there are (10+7+5) =22 prizes. Out of these 22 prizes, three are to be chosen at a time.
n(S)= C (22,3)

a) The probability that exactly two $20 prizes are chosen is given as:
p=n(E)/n(S) ...

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