Normal Subgroups, Centralizers and Semi-Direct Products
Not what you're looking for?
1. I f A and B are normal subgroups of G such that G/A and G/B are abelian, prove that G/(A intersect B) is abelian
2. Let H and K be groups, let f be a homomorphism from K into Aut(H) and as usual identify H and K as subgroups of G= H x_f K( x_f denotes product of H and K under f).
Prove that C_K(H)= Ker(f)
ps. C_K(H) is centralizer
keywords: semi direct
Purchase this Solution
Solution Summary
Normal Subgroups, Centralizers and Semi-Direct Products are investigated.
Solution Preview
1. Proof:
We use A^B to denote "A intersect B".
We consider two element g(A^B) and h(A^B) in G/(A^B), we want to show
that g(A^B) * h(A^B) = gh(A^B) = h(A^B) * g(A^B) = hg(A^B)
That is equivalent to show that g^(-1)h^(-1)gh belongs to A^B.
Since G/A is abelian, then gA and hA are commutative, so we have
gA * hA = ghA = hA * gA = hgA.
This implies that ...
Purchase this Solution
Free BrainMass Quizzes
Geometry - Real Life Application Problems
Understanding of how geometry applies to in real-world contexts
Know Your Linear Equations
Each question is a choice-summary multiple choice question that will present you with a linear equation and then make 4 statements about that equation. You must determine which of the 4 statements are true (if any) in regards to the equation.
Exponential Expressions
In this quiz, you will have a chance to practice basic terminology of exponential expressions and how to evaluate them.
Multiplying Complex Numbers
This is a short quiz to check your understanding of multiplication of complex numbers in rectangular form.
Probability Quiz
Some questions on probability