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Integrating Factors

Using: d tan^-1 (x/y)=(y dx - x dy)/(x^2 + y^2), and ½ d ln(x^2 + y^2)=(x dx + y dy)/(x^2 + y^2) find integrating factors for, and solve, the following equation:
(2x^(2)y + 2y^3 - x) (dy/dx) + y=0

Solution Preview

your tan^-1 (x/y) means tan(x/y). Then the formula
d tan^-1 (x/y)=(y dx - x ...

Solution Summary

This shows how to find integrating factors and solve an equation.