# maximum height when a stone is thrown upward

I am pretty sure I have a and b. I am not sure how to get the time it would be at maximum height and what the maximum height is.

The path of a falling object is given by the function s = -16t^2 + v0t + s0, where represents the initial velocity in ft/sec and represents the initial height in feet.

a) If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25-foot building, write the height (s) equation using this information.

Typing hint: Type t-squared as t^2

b) How high is the rock after 1 second?

c) After how many seconds will the graph reach maximum height?

d) What is the maximum height?

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(a) s = -16t^2 + 64t + ...

#### Solution Summary

The solution is comprised of detailed explanation of the motion and path when an object is thrown upward with a certain initial velocity. It also demonstrates on how to find the maximum height of the stone.