I am pretty sure I have a and b. I am not sure how to get the time it would be at maximum height and what the maximum height is.
The path of a falling object is given by the function s = -16t^2 + v0t + s0, where represents the initial velocity in ft/sec and represents the initial height in feet.
a) If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25-foot building, write the height (s) equation using this information.
Typing hint: Type t-squared as t^2
b) How high is the rock after 1 second?
c) After how many seconds will the graph reach maximum height?
d) What is the maximum height?© BrainMass Inc. brainmass.com October 9, 2019, 8:12 pm ad1c9bdddf
Please see the attached file for detailed solution.
(a) s = -16t^2 + 64t + ...
The solution is comprised of detailed explanation of the motion and path when an object is thrown upward with a certain initial velocity. It also demonstrates on how to find the maximum height of the stone.