Explore BrainMass

Explore BrainMass

    maximum height when a stone is thrown upward

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    I am pretty sure I have a and b. I am not sure how to get the time it would be at maximum height and what the maximum height is.

    The path of a falling object is given by the function s = -16t^2 + v0t + s0, where represents the initial velocity in ft/sec and represents the initial height in feet.

    a) If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25-foot building, write the height (s) equation using this information.

    Typing hint: Type t-squared as t^2

    b) How high is the rock after 1 second?

    c) After how many seconds will the graph reach maximum height?

    d) What is the maximum height?

    © BrainMass Inc. brainmass.com December 24, 2021, 6:50 pm ad1c9bdddf

    Solution Preview

    Please see the attached file for detailed solution.

    (a) s = -16t^2 + 64t + ...

    Solution Summary

    The solution is comprised of detailed explanation of the motion and path when an object is thrown upward with a certain initial velocity. It also demonstrates on how to find the maximum height of the stone.