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Ball & stone thrown at different times & meet at same height

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A ball is thrown vertically upward with an initial speed of 22 m/s. Then, 0.67s later, a stone is thrown straight up (from the same initial height as the ball) with an initial speed of 37 m/s.

How far above the release point with the ball and stone pass each other? The acceleration of gravity is 9.8 m/s^2.
Answer in units of m.

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Solution Summary

In this exercise, a stone is thrown 0.67 seconds later than the ball, given the intial speeds of both the stone and the ball. Students are asked to find the height where the stone and the ball meet.

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Solution:
Let the time the stone travel be t, so the time the ball travel will be t + 0.67, in units of seconds

Let the ...

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