# Heat Equation on Circle

Solve the heat problem on the circle

u_t = ku_{xx}

u(x,0) = phi(x) where phi(x) is the 2l periodic extension of phi

using the separation of variables.

I am able to go as far as

u = XT

-X''/X = lambda where lambda = beta^2

usually the solution for X'' + beta^2 * X = 0 is Ccos(beta * L) + D sin(beta * L) I believe.

using cos = (e^i + e^-i)/2 and sin...

X(x) = C[(e^iBx + e^iBx)/2 + D(e^ibx - e^-iBx)/2i]

T(x) = Ae^B^2kt

B = beta and C, D, and A are coeff

I do not know how to find the coefficients.

There is no directly stated boundary conditions.

I think I'm supposed to assume something.

How do I solve for the coefficients?

https://brainmass.com/math/fourier-analysis/heat-equation-circle-157787

#### Solution Summary

The heat equation on circle is investigated. The solution is detailed and well presented.

$2.19