# Equation of a circle

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Find the equation of the circle satisfying the given conditions:

Center (2,-1) and goes through (5,3).

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##### Solution Summary

This shows how to write the equation of a circle given center and point on the circle.

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Let the radius of the circle is r.

Hence, Eqn of the circle is given as:

(x-xo)^2 + (y-yo)^2 = r^2

where, (xo,yo) = (2,-1) ...

###### Education

- BEng, Allahabad University, India
- MSc , Pune University, India
- PhD (IP), Pune University, India

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