Explore BrainMass
Share

Explore BrainMass

    Mathematics - Finite Mathematics

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    My question is as follows:

    Suppose that you are given a simple chain of length N beads, and in this chain you tie one knot in the centre. You perform an experiment 25 times in which each time you place the chain on a vibrating plate and measure how long it takes to unknot and you make a list of the un-knotting times as follows:
    chain1 = {5.50, 8.10, 4.65, 4.03, 14.04, 9.94, 10.34, 3.47, 5.19,
    8.54, 5.63, 5.53, 5.38, 3.44, 4.32, 12.69, 5.66, 2.34, 14.72, 5.07,
    5.90, 6.60, 4.75, 5.59, 4.85}

    From this we calculated the mean un-knotting time is: 6.6508, with standard deviation 3.2977.

    My question is how can one find the probability based on the data above of finding the knot still knotted (i.e., still "alive") at time t.

    © BrainMass Inc. brainmass.com October 9, 2019, 10:03 pm ad1c9bdddf
    https://brainmass.com/math/discrete-math/finite-mathematics-probability-mean-unknotting-time-206242

    Solution Preview

    m = 6.6508, s = 3.2977, n = 25

    Standard Error of the mean unknotting time = s/ sqrt n = 3.2977/ sqrt 25 = 0.6595

    We want to find the probability that the knot is still knotted at time ...

    Solution Summary

    A complete, neat and step-by-step solution that calculates the mean unknotting time.

    $2.19