# Differentiation

Differentiation

1. Show that if the tangent to y=ekx at (a, eka) passes through the origin then a=1/k.

2. Find the value of a and b so that the line 2x +3y = a is tangent to the graph of f(x)=bx2 at the point where x = 3.

See attached file for full problem description.

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#### Solution Preview

Please see the attached file.

1. Show that if the tangent to y=ekx at (a, eka) passes through the origin then a=1/k

Solution:

Differentiating the given function, we get y'=kekx. At the point (a, eka) the slope of the tangent is ...

#### Solution Summary

This is a proof regarding the tangent and shows how to find values so that a given line is a tangent to a given curve.

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