Differentiation
Differentiation
1. Show that if the tangent to y=ekx at (a, eka) passes through the origin then a=1/k.
2. Find the value of a and b so that the line 2x +3y = a is tangent to the graph of f(x)=bx2 at the point where x = 3.
See attached file for full problem description.
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Solution Preview
Please see the attached file.
1. Show that if the tangent to y=ekx at (a, eka) passes through the origin then a=1/k
Solution:
Differentiating the given function, we get y'=kekx. At the point (a, eka) the slope of the tangent is ...
Solution Summary
This is a proof regarding the tangent and shows how to find values so that a given line is a tangent to a given curve.
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