Find the general solution of the differential equation: y'' + 2y' + 2y = 2e^(-x) tan^2 x.© BrainMass Inc. brainmass.com November 30, 2021, 12:01 am ad1c9bdddf
Consider this homogenous equation:
y'' + 2y' + 2y=0
It has two solution finctions, y1=e^(-x)sin(x) and y2=e^(-x)cos(x)
Then we consider a general solution like:
y=uy1=u*e^(-x)sin(x) where u is unknown. ...
A solution to a differential equation is found.