Find the general solution of the differential equation: y'' + 2y' + 2y = 2e^(-x) tan^2 x
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Find the general solution of the differential equation: y'' + 2y' + 2y = 2e^(-x) tan^2 x.
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Solution Preview
Consider this homogenous equation:
y'' + 2y' + 2y=0
It has two solution finctions, y1=e^(-x)sin(x) and y2=e^(-x)cos(x)
Then we consider a general solution like:
y=uy1=u*e^(-x)sin(x) where u is unknown. ...
Solution Summary
A solution to a differential equation is found.
$2.49