# Find the general solution of the differential equation: y'' + 2y' + 2y = 2e^(-x) tan^2 x

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Find the general solution of the differential equation: y'' + 2y' + 2y = 2e^(-x) tan^2 x.

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##### Solution Summary

A solution to a differential equation is found.

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Consider this homogenous equation:

y'' + 2y' + 2y=0

It has two solution finctions, y1=e^(-x)sin(x) and y2=e^(-x)cos(x)

Then we consider a general solution like:

y=uy1=u*e^(-x)sin(x) where u is unknown. ...

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