# Find the general solution of xy' - y = 2y (ln y - ln x).

Find the general solution, if possible. Otherwise find a relation that defines the solutions implicitly:

xy' - y = 2y (ln y - ln x)

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xy' - y = 2y(ln y - ln x)

put, y = vx

y' = dy/dx = v + x dv/dx

hence,

xv + x^2 ...

#### Solution Summary

This shows how to find the general solution of a differential equation.

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