Find the general solution of xy' - y = 2y (ln y - ln x).
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Find the general solution, if possible. Otherwise find a relation that defines the solutions implicitly:
xy' - y = 2y (ln y - ln x)
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xy' - y = 2y(ln y - ln x)
put, y = vx
y' = dy/dx = v + x dv/dx
hence,
xv + x^2 ...
Solution Summary
This shows how to find the general solution of a differential equation.
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