Find the general solution of the differential equation: y'' - 2y' + y = (e^x)/x© BrainMass Inc. brainmass.com February 24, 2021, 2:21 pm ad1c9bdddf
Taking the homogeneous part as: y''-2y'+y =0
we get the characteristic equation as r^2 - 2r + 1 = 0,
or (r-1)^2 = 0
whose solution is given as: r1=1, r2=1
Here r1 = ...
The expert finds the general solution of the differential equations.