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Differential equation

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Find the general solution of the differential equation: y'' - 2y' + y = (e^x)/x

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Solution Summary

The expert finds the general solution of the differential equations.

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Taking the homogeneous part as: y''-2y'+y =0
we get the characteristic equation as r^2 - 2r + 1 = 0,
or (r-1)^2 = 0
whose solution is given as: r1=1, r2=1
Here r1 = ...

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