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    Q#1) Find the equation of the tangent line to y = 2 ln x at the point where x = 8.

    y = x/2 - 1 + ln 2
    y = x/2 - 1 + 2 ln 2
    y = x/4 - 1 + ln 2
    y = x/4 - 2 + 6 ln 2
    y = x/8 - 1 + ln 2
    y = x/8 - 1 + 2 ln 2
    y = x/8 - 1 + 3 ln 2
    none of these

    Q#2) If f(x) = (x + 2 ln x)^2 , then f '(x) =

    (2/x)(x + 1)(x + ln x)
    (2/x)(1 + ln x)
    (2/x)(x + 2)(x + 2 ln x)
    (2/x)(x + 2 ln x)
    (4/x)(1 + 2 ln x)
    (4/x)(x + 2)(x + 2 ln x)
    none of these

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    https://brainmass.com/math/calculus-and-analysis/2-objective-question-139008

    Solution Preview

    Q#1) Find the equation of the tangent line to y = 2 ln x at the point where x = 8.

    y = x/2 - 1 + ln 2
    y = x/2 - 1 + 2 ln 2
    y = x/4 - 1 + ln 2
    ...

    $2.49

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