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Cooling of soup

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A bowl of soup at 185 degree F is left in a room with a temperature of 75 degree F to cool.

- 0.075^t : After t minutes, the temperature, T, of the soup is given T(t)= 75 + 110e

Find the temperature of the soup 24 minutes after it is left in the room (round to the nearest degree).

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Solution Summary

Evaluating exponential functions for different given values.

Solution provided by:
Chris Busu, PhD (IP)
Education
  • BSc, University of Bucharest
  • MSc, Ovidius
  • MSc, Stony Brook
  • PhD (IP), Stony Brook
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