If a rock is thrown into the air on small planet with a velocity of 25 meters/second, its height in meters after t seconds is given by V = 25t ? 4.9t2. Find the velocity of the rock when t=3
A particle moves along a straight line and its position at time t is given by s(t) = 2t3 ? 27t2 + 108t where s is measured in meters and t in seconds.
Find the velocity of the particle at time t = 0: _______________ meters/second.
The particle stops moving (i.e. is in a rest) twice, once when t=A and again at t = B where A < B.
A is ____________seconds,
and B is _____________ seconds.
What is the position of the particle at time 18? ________________________ meters.
Finally, what is the TOTAL distance the particle travels between time 0 and time 18? ____________________________ meters.
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The solution is attached below (next to the paperclip icon) in two formats. one is in Word XP Format, while the other is in Adobe pdf format. ...
Velocity, Time, Distance of a Rock After it has been Thrown are investigated. The solution is detailed and well presented.