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Quadratic Equations: How Long Until an Object Hits the Ground?

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Question: A rock is thrown from the top of a building. The distance, in feet, between the rock and the ground t seconds after the rock is thrown is given by d = -16t^2 + 16t + 45. How long after the rock is thrown does it hit the ground?

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Solution Summary

In about 70 words, this solution is comprised of a complete, neat and step-by-step response which illustrates how to calculate for time in seconds, for this particular scenario.

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d = -16t^2 + 16t + 45

When the rock hits the ground, d = 0

= -16t^2 ...

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