An object is projected vertically upward from the top of a building with an initial velocity of 144 ft/second. It's distance, s(t) in feet above the ground after t seconds is given by the equation: s(t)=-16^2+144t+100
- find the maximum height, s(t), of the object above the ground.
- find the height of the building, that is, at t=0.
A word problem is solved regarding an object that is thrown upward.