How long does it take to transmit a 10baseT Ethernet frame that contains 256 bytes of data? Ignore the interframe gap that follows the frame.
1. Find the total number of bytes in the frame.
2. Convert the total bytes into total bits.
3. Multiply the total bits by the time for one bit.
4. Repeat steps 1 through 3 for a frame containing 800 bytes of Data.
Preamble = (7+1) = 8 bytes
MAC header = 6+6+4+2 = 18 bytes
LLC protocol data unit = 1+1+2+256 = 260
MAC trailer = 4 bytes
Total number of bytes/frame = ...
Solution provides details of a 10base Ethernet frame.