Purchase Solution

Moles

Not what you're looking for?

Ask Custom Question

A package of M&M candies contains 50 pieces. What fraction of a mole is this? Express in both normal and scientific notation.

A package of 50 m&m candies cost 50 cents. How much would a mole of m&m's cost in dollars? Given the annual budget of the US is 2 trillion dollars, how many years would it take the US to pay for a mole of m&m candies?

Purchase this Solution
Solution Summary

The solution calculates the number of moles for a package of M&M candies.

Solution Preview

1 mole= 6.023E+23 or 6.023 x 10^23 particles

A package of M&M candies contain 50 pieces
Expressed as a fraction of a mole it is equal to
50/(6.023 x ...

Purchase this Solution
Free BrainMass Quizzes
Organic Chemistry Naming: Alkanes

This is a quiz which is designed to assist students with learning the nomenclature used to identify organic compounds. This quiz focuses on the organic compounds called Alkanes.

Match Elements with their Symbols

Elements are provided: choose the matching one- or two-letter symbol for each element.

Periodic table

General Chemistry - Classification of Matter

This test will assess your knowledge on the classification of matter which includes elements, compounds and mixtures.

Functional groups in Organic Chemistry

You will be tested on the names of functional groups in Organic Chemistry. It is very important to know the functional groups to understand Organic reactions.

View More Free Quizzes
Related BrainMass Solutions

  • Moles of Aluminum, Sulfur and Oxygen Atoms

    Assuming 8.00 moles Aluminum sulfate is given: 8.00 moles Al2(SO4)3 x 2 moles Al / mole Al2(SO4)3 = 16 moles Al 8.00 moles Al2(SO4)3 x 3 moles S / mole Al2(SO4)3 = 24 moles S 8.00 moles Al2(SO4)3 x 12 moles O / mole Al2(SO4)3 = 96 moles O

  • Using Stoichiometry Ratios

    1.) 5 moles of C = 1 mole of CS2 Therefore, 2.7 moles of C = 2.7/5 = 0.54 moles of CS2 (Answer) 2.) 2 moles of SO2 reacts with C = 5 moles Therefore, 5.44 moles of SO2 will react with C = 5*5.44/2 = 13.6 moles (Answer) 3.)

  • Stoichiometry Reaction Maximum Amount

    = 32 Number of moles of O2 = 1.16/32 = 0.03625 moles 1 mole of O2 combines with 2 moles of CO to give 2 moles of CO2 Hence 0.03625 moles of O2 would combine with 2*0.03625 = 0.0725 moles of CO to yield 0.0725 moles of CO2 Therefore, maximum moles

  • Mass balance

    Propylene 5.2 mole/ 100 moles Propane X mole/ 100 moles = 14.1 mole/ 100 moles Ethylene 1.9 mole/ 100 moles Ethane 2.1/ 100 moles Isobutene 4.8/ 100 moles (given) total1 = 28.1 moles And at the bottom column the following components are

  • Working with amount of gases produced and consumed

    we know that 2moles of butane require 13 moles of O2 (from the balanced equation) so 1 mole require 13/2 moles of O2 thus 0.3414 moles require 0.3414*13/2 moles of O2 = 2.2191 moles of O2 is required.

  • Partial pressure, mole fraction, total pressure and pressure conversion.

    N2 + O2 + He + CO2 3 moles 2 moles 1.5 moles 1.8 moles Total no. of mole = sum of the no. of moles = (3 + 2 + 1.5 + 1.8) moles = 8.3 moles Mole fraction of N2 = 3moles/8.3moles = XN2 = 0.3614

  • Solubility and Titration

    = 0.25 M × 0.035 L = 8.75 × 10-3 moles Moles of HF reacted = 8.6734 × 10-3 moles Moles of F- produced = Moles of HF reacted = 8.6734 × 10-3 moles [F-] = moles / total volume =

  • Chemical Quantities

    Moles of Ag+ = 3.062  10-3 moles = moles of AgNO3 mass of AgNO3 = moles * molar mass = 3.062  10-3 moles * 169.873 g mol-1 = 0.52 g moles of AgCl produced = 3.062  10-3 moles molecules = moles * NA = 3.062

  • Concentration and Dilution

    So the new concentration will be, = 0.00256/ 100*10^-3 L = 0.0256 moles/L = 0.0256 M b) Total number of moles of FeCl3 in 100mL (taken from the above solution) = 0.0256 * 100*10^-3 moles = 0.00256 moles.

  • Calculating moles of reactants and products and interchanging between volume and moles at constant pressure

    Since looking at the stoichiometric cooficients we see that every 2 KClO3 moles produce 3 O2 moles we ca safely establish the following 2 moles KCLO3 -----> 3 moles O2 x moles KClO3 -----> how many moles of O2?

View More Related Solutions