Calculate the concentration of all the following.
A solution of FeCl3 was prepared by dissolving 13.86 gm of FeCl3 in 2.5L of water. The following solutions were then prepared by dilution:
Solution A: 75.0 mL of the above solution was diluted to 100.0mL
Solution B: 100.0 mL of solution A was diluted to 2500 mL
Solution C: 5.0 mL of solution B was diluted to 1500mL
Molecular weight of FeCl3 = 162.2 g/mole
Number of moles of FeCl3 = 13.86/162.2 = 0.0854 moles.
We are dissolving 0.0854 moles in 2.5L of water.
So the concentration of this solution is = 0.0854/2.5
= 0.0342 moles/L = 0.0342 M
0.0342 is the number of moles ...
This solution is provided in 218 words and demonstrates how to find concentration and moles to find concentration after dilution.
Concentration : Dilution Problem
A student placed 18.5g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 60.0-mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution?View Full Posting Details