Ten grams of hamburger were added to 90 mL of sterile buffer. This was mixed well in a blender. One-tenth of a mL of this slurry was added to 9.9 mL of sterile buffer. After thorough mixing, this suspension was further diluted by successive 1/100 and 1/10 dilutions. One-tenth of a mL of this final dilution was plated onto Plate Count Agar. After incubation, 52 colonies were present. How many colony-forming units were present in the TOTAL 10 gram sample of hamburger?© BrainMass Inc. brainmass.com October 17, 2018, 4:47 am ad1c9bdddf
Ten grams of hamburger were added to 90 mL of sterile buffer. After blending this with sterile buffer, you have concentration of X in the hamburger/sterile buffer. You are making dilutions to find a concentration, after which you will have colony forming units. Colony forming units are colonies of bacteria that form from the replication of a single bacteria. So if you can dilute your sample to a ...
This solution helps find the number of colony-forming units given information about dilutions. A step by step explanation is given, in 285 words.
please help me understand the following dilution schemes
Consider the following dilution scheme:
A. 1oomL lake water
B. 5mL lake water into 45 mL diluent 0.1 ml - colonies TNTC
C. 1mL from B into 9ml diluent 0.1 ml - colonies 425
D. 0.5mL from C into 4.5 mL diluent 0.1 ml - colonies 58
E. 2mL from D into 19mL diluent 0.1 ml - colonies 12
F. 0.1mL from E into 0.9 mL diluent 0.1 ml - colonies 1
a. What dilution is achieved by adding 2mL of incoulum to 19mL of a diluent?
b. Would you expect any change in the answer of the above problem if the firat dilution was made by adding 1 mL of sample to 9 mL of diluent? Why or why not?
c. What are the total number of CFU's in the entire 100mL amount of the original lake water sample?
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