Please see the attached file for full problem description.
Q1. Starting with a pulp with a water content of 99%, how much water must be removed to obtain one ton of paper containing 60% water?
Pulp 1-ton paper
99 % H20 60% H20
Basis: 100 ton of paper
Let x represent the pulp used to produce paper
Let y represent the paper created by the pulp.
Let w represent the water removed by the evaporator.
X = W +Y
(99/100) X = W(0) + 1(60/100)
X = 0.60
Substitute into equation to calculate the amount of water removed.
0.60 = W + 1
0.40 = W