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# Solving a PH Problem

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What is the pH value of water containing 0.005 M of an acid with a acid dissociation constant of 0.001 M. The dissociation of the acid in water can be represented as: HA <-> H+ + A-

Ka=[H][A]/[HA]

Kw=[OH][H]=10^-14

Mass balance equation: Cta=[HA]+[A](MBE)

Charge balance equation: CB = [H]=[A-]+[OH-]

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Ka=0.001 M
CHA=0.005 M

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#### Solution Summary

This solution is comprised of a detailed, step-by-step explanation of how to solve for pH for the following question, which requires the use of two different equations: the mass balance equation and the charge balance equation. In order to view the solution, a word file attachment needs to be opened. This outlined solution is a great model to follow for future questions of this nature.

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