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    Limiting reactants

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    Suppose 358 g aluminum sulfide react with 124 g water.

    Al2S3 + H2O -> Al(OH)3 + H2S unbalanced!

    What mass of the excess reactant remains?

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    Solution Preview

    Balanced equation:
    Al2S3 + 6H2O -> 2Al(OH)3 + 3H2S

    Molecular wt of aluminium sulphide = 2*27+3*32 = 150
    Molecular wt of water = ...

    Solution Summary

    The answer is given step-by-step equationally. The expert examines limiting unbalanced reactants. The aluminum sulfide reacts are given.