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Equivalent weight

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Please help me solve the problem in the attachment.

First of all, I don't understand exactly what equivalent weight is.
Secondly, I know that the coefficient of variation is CV = (s/x) x 100%
So, what does the % analyte formula in the problem statement have to do with anything?

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Solution Summary

The equivalent weights of a compound are determined.The answer is given step-by-step equationally.

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%A = tritrant volume x equivalent weight x 100/sample weight
=>%A= (final -initial buret reading)*equivalent weight*100/sample weight

Final reading F = 8.76 mL +- 0.03 mL
Initial reading I = 0.23 mL +- 0.02 mL
Sample weight W = 50 ...

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  • BEng, Allahabad University, India
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  • PhD (IP), Pune University, India
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