# Equivalent weight

Please help me solve the problem in the attachment.

First of all, I don't understand exactly what equivalent weight is.

Secondly, I know that the coefficient of variation is CV = (s/x) x 100%

So, what does the % analyte formula in the problem statement have to do with anything?

Thanks.

https://brainmass.com/chemistry/stoichiometry/equivalent-weight-24979

#### Solution Preview

Because,

%A = tritrant volume x equivalent weight x 100/sample weight

=>%A= (final -initial buret reading)*equivalent weight*100/sample weight

Final reading F = 8.76 mL +- 0.03 mL

Initial reading I = 0.23 mL +- 0.02 mL

Sample weight W = 50 ...

#### Solution Summary

The equivalent weights of a compound are determined.The answer is given step-by-step equationally.

$2.19