Purchase Solution

Equivalent weight

Not what you're looking for?

Ask Custom Question

Please help me solve the problem in the attachment.

First of all, I don't understand exactly what equivalent weight is.
Secondly, I know that the coefficient of variation is CV = (s/x) x 100%
So, what does the % analyte formula in the problem statement have to do with anything?
Thanks.

Attachments
Purchase this Solution
Solution Summary

The equivalent weights of a compound are determined.The answer is given step-by-step equationally.

Solution Preview

Because,
%A = tritrant volume x equivalent weight x 100/sample weight
=>%A= (final -initial buret reading)*equivalent weight*100/sample weight

Final reading F = 8.76 mL +- 0.03 mL
Initial reading I = 0.23 mL +- 0.02 mL
Sample weight W = 50 ...

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
Recent Feedback
  • " In question 2, you incorrectly add in the $3.00 dividend that was just paid to determine the value of the stock price using the dividend discount model. In question 4 response, it should have also been recognized that dividend discount models are not useful if any of the parameters used in the model are inaccurate. "
  • "feedback: fail to recognize the operating cash flow will not begin until the end of year 3."
  • "Answer was correct"
  • "Great thanks"
  • "Perfect solution..thank you"
Purchase this Solution
Free BrainMass Quizzes
Periodic table

General Chemistry - Classification of Matter

This test will assess your knowledge on the classification of matter which includes elements, compounds and mixtures.

Functional groups in Organic Chemistry

You will be tested on the names of functional groups in Organic Chemistry. It is very important to know the functional groups to understand Organic reactions.

Match Elements with their Symbols

Elements are provided: choose the matching one- or two-letter symbol for each element.

Organic Chemistry Naming: Alkanes

This is a quiz which is designed to assist students with learning the nomenclature used to identify organic compounds. This quiz focuses on the organic compounds called Alkanes.

View More Free Quizzes
Related BrainMass Solutions

  • Acid-Base Titration

    KHC8H4O4's is equivalent weight 204.2g/equiv number of gram equivalent of KHC8H4O4 = mass/equivalent weight = 0.394 / 204.2 = 1.93 x 10^-3 using normality equation, N1V1 = N2V2 (KHC8H4O4) (NaOH

  • Solve: Calculating the Equivalent Weight of an Unknown Substance

    Does your structure agree with the calculated equivalent weight? Please see that attached pdf document for the solution. Hope it helps. Thanks for using Brainmass. The expert calculates the equivalent weight of an unknown substance.

  • Molecular weight molarity

    Molecular weight: NaHCO3=23+1+12+16*3=84g/mol. Since you have 4.12 grams, equivalent to: 4.12/84=0.05(mole) So you should dissolve it in 50 mL of water to make 1M solution.

  • Stoichiometry Problems and Chemical Equations

    Molar mass = 136.15 g/mol Hence, Equivalent weight = (136.15 g/mol) / (1 eq / mol) Equivalent weight = (136.15 g/eq) 6) It was found that 19.60 mL of NaOH solution were required to neutralize 10.00 mL of HCL.

  • Bainbridge Mass Spectrometer

    The equivalent weight of lithium is examined using Bainbridge Mass Spectrometer. The magnetic flux density is analyzed.

  • Given that the average TEQ of animal-based foods is

    319616 Given that the average TEQ of animal-based foods is about 0.9 picograms of TCDD equivalent per gram, and that the LD50 for 2,3,7,8-TCDD is about 0.001 mg/kg body weight, what mass(kg) of animal-based food would you have to consume to ingest a fatal

  • Ksp and Normality

    Hence equivalent weight = formula weight / 3 = 158/3 = 52.67 0.6M solution contains 0.6 mol in 1L. Mass of KMnO4 = 0.6 x 158 = 94.8g Hence normality = mass / (Volume x equivalent weight) = 1.8N Q2. Mol of Cr = 0.2 x 0.3 = 0.06.

  • Toxicity of TCDD in Animal Based Foods

    164976 Toxicity of TCDD in Animal Based Foods Given that the average TEQ of animal-based foods is about 0.7 picograms of TCDD equivalent per gram, and that the LD50 for 2,3,7,8-TCDD is about 0.001 mg/kg body weight, what mass(kg) of animal-based food

  • Calculate the number of grams of citric acid

    Molecular weight of NaOH=23+16+1=40(g/mol) The number of mole required=molarity*volume=0.5*0.25=0.125(mol) You need 0.125 mole of NaOH, which is equivalent to 0.125*40=5(g) So you need 5 grams of NaOH. 3.

View More Related Solutions