Please help me solve the problem in the attachment.
First of all, I don't understand exactly what equivalent weight is.
Secondly, I know that the coefficient of variation is CV = (s/x) x 100%
So, what does the % analyte formula in the problem statement have to do with anything?
%A = tritrant volume x equivalent weight x 100/sample weight
=>%A= (final -initial buret reading)*equivalent weight*100/sample weight
Final reading F = 8.76 mL +- 0.03 mL
Initial reading I = 0.23 mL +- 0.02 mL
Sample weight W = 50 ...
The answer is given step-by-step equationally.