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Molecular weight molarity

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Please assist with creating 1.0 M solution with 5.21 grams of Na2CO3.

I need to create 1.0 M solution with 4.12 grams of NaHCO3 .

How much distilled water to is use to create these 1.0 M solutions.

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Solution Summary

The solution provides a detailed and step-by-step explanation for the problem regarding molecular weight molarity..

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Molecular weight: Na2CO3=23*2+12+16*3=106g/mol.
1M means 1 mole/litre. Since you have 5.21 ...

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