Explore BrainMass
Share

# Titration, solution content and molarity

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

An experiment calls for using 20 mL of toluene. (density=0.8668 g/mL, molecular weight=92.139 g/mol). What mass of toluene, and how many moles are involved?

An experiment calls for 50.0 of benzoyl chloride to be used (density=1.212 g/mL). What volume of benzoyl chloride is needed?

An aqueous solution of nitric acid has a density of 1.41 g/mL and contains 70.0% HNO3 by weight (wt/wt). What is the molarity of this solution?

https://brainmass.com/chemistry/compounds/titration-solution-content-molarity-588859

#### Solution Preview

1. Volume, V = 20 mL
density, d = 0.8668 g/mL

Hence, mass of toluene, m = volume * density = V*d = 20*0.8668 = 17.336 g

molecular weight of toluene, M = 92.139 g/mol

Hence, number of moles involved in reaction = mass/molecular wt = ...

#### Solution Summary

This solution explains and answers three problems of titration.

\$2.19