Titration, solution content and molarity
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An experiment calls for using 20 mL of toluene. (density=0.8668 g/mL, molecular weight=92.139 g/mol). What mass of toluene, and how many moles are involved?
An experiment calls for 50.0 of benzoyl chloride to be used (density=1.212 g/mL). What volume of benzoyl chloride is needed?
An aqueous solution of nitric acid has a density of 1.41 g/mL and contains 70.0% HNO3 by weight (wt/wt). What is the molarity of this solution?
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Solution Summary
This solution explains and answers three problems of titration.
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1. Volume, V = 20 mL
density, d = 0.8668 g/mL
Hence, mass of toluene, m = volume * density = V*d = 20*0.8668 = 17.336 g
molecular weight of toluene, M = 92.139 g/mol
Hence, number of moles involved in reaction = mass/molecular wt = ...
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